m^2+3/4=21

Solution for m^2+3/4=21 equation:

m^2+3/4=21

We move all terms to the left:

m^2+3/4-(21)=0

determiningTheFunctionDomain
m^2-21+3/4=0

We multiply all the terms by the denominator


m^2*4+3-21*4=0

We add all the numbers together, and all the variables

m^2*4-81=0

Wy multiply elements

4m^2-81=0

a = 4; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·4·(-81)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*4}=\frac{-36}{8}
=-4+1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*4}=\frac{36}{8}
=4+1/2
$